Thread: the derivative function

given that f(3)=-1 and f '(3)=5, find an equation for the tangent line to the graph of y=f(x) at x=3

no idea where to start

There is a formula stating that the equation of the tangeant to a curve at point A (a, f(a)) is:

y-f(a)=(x-a)f'(a)


civodul

i know the answer is y=5x-16 but not seeing how you get to that from that equation

Just plug in the values for the formula



and then simplify