given that f(3)=-1 and f '(3)=5, find an equation for the tangent line to the graph of y=f(x) at x=3 no idea where to start
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There is a formula stating that the equation of the tangeant to a curve at point A (a, f(a)) is: y-f(a)=(x-a)f'(a) civodul
i know the answer is y=5x-16 but not seeing how you get to that from that equation
Just plug in the values for the formula $\displaystyle y - (-1) = 5(x-3)$ and then simplify
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