given that f(3)=-1 and f '(3)=5, find an equation for the tangent line to the graph of y=f(x) at x=3

no idea where to start

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- Sep 28th 2008, 02:02 PMvinson24the derivative function
given that f(3)=-1 and f '(3)=5, find an equation for the tangent line to the graph of y=f(x) at x=3

no idea where to start - Sep 28th 2008, 02:13 PMcivodul
There is a formula stating that the equation of the tangeant to a curve at point A (a, f(a)) is:

y-f(a)=(x-a)f'(a)

civodul - Sep 28th 2008, 02:17 PMvinson24
i know the answer is y=5x-16 but not seeing how you get to that from that equation

- Sep 28th 2008, 02:21 PM11rdc11
Just plug in the values for the formula

$\displaystyle y - (-1) = 5(x-3)$

and then simplify