# displacement vector problem

• Sep 28th 2008, 02:52 AM
yzc717
displacement vector problem
• Sep 28th 2008, 07:38 AM
o_O
Since the airplane is travelling at a constant height, then your j component stays the same.

Now, you know that the airplane is travelling at a constant velocity. You are given that in 30 seconds, it travels $9.24 \cdot 10^3$ metres. So, $v = \frac{d}{t} = \frac{9.24 \cdot 10^3 \ \text{metres}}{30.0 \ \text{s}} = 308 \ ms^{-1}$

So how far will it have travelled in 70 seconds? This will be your i-component.

Now use that position vector and find its magnitude and angle with respect to the x-axis.
• Sep 28th 2008, 12:47 PM
yzc717
Quote:

Originally Posted by skeeter
$9.24 \times 10^3$ meters in 30 sec is $3.08 \times 10^2$ meters per second.
can you now determine the horizontal displacement at t = 70 seconds?
the vertical component does not change.
finish the problem ... find the magnitude and direction of the position vector at t = 70 seconds.

i still have it wrong
21560 m
it tells me Your answer is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation.
• Sep 28th 2008, 01:47 PM
o_O
Show us what you have done. It should work out.
• Sep 28th 2008, 02:11 PM
yzc717
Quote:

Originally Posted by o_O
Show us what you have done. It should work out.

i got it now.

it is the resultant, not the horizontal thing i got before.