Find the equation for the plane tangent to the surface z = f(x,y) at the indicated point: $\displaystyle z = x^3 + y^3 - 6xy, (1,2,-3)$ I get stuck at finding the third component of the gradient of z.
Follow Math Help Forum on Facebook and Google+
Originally Posted by Aryth Find the equation for the plane tangent to the surface z = f(x,y) at the indicated point: $\displaystyle z = x^3 + y^3 - 6xy, (1,2,-3)$ I get stuck at finding the third component of the gradient of z. the tangent plane to a curve $\displaystyle z = f(x,y)$ at a point $\displaystyle (x_0,y_0,z_0)$ is given by $\displaystyle z - z_0 = f_x(x_0,y_0)(x - x_0) + f_y(x_0,y_0)(y - y_0)$
View Tag Cloud