I cant solve this problem:

INTEGRAL OF: (x^3-4x^2-16) / (x^3-4x^2)

I change the denominator into (x^2)(x-4) and setup the following partial fraction:

A/x + (Bx+C)/x^2 + D/x-4

When you multiply the numerators by the other two denominators though you don't get a term without an x, thus your left with nothing to set equal to 16.