Definite integral ln(1+t)dt

I need some help with a particular question that i can't seem to figure out no matter how much time i've spent on it this evening..

$\displaystyle \int_{0}^{5} ln(1+t)dt$

My first way of thinking led me to a dead end. I used integration by parts with $\displaystyle U=ln(1+t)$ and $\displaystyle U`=1/(1+t)$ and $\displaystyle V`=1dt$ and $\displaystyle V=t$

This led me to the following

$\displaystyle = [tln(1+t)]_{0}^{5} - \int_{0}^{5} t/(1+t)dt $

and this is where i'm stuck.. can't seem to figure out the integration for the second integral here.

I think my line of thinking is wrong.. is my assumption that $\displaystyle U=ln(1+t)$ and $\displaystyle U`=1/(1+t)$ incorrect?