if $\displaystyle y e^{xy} = Sinx$ find dy/dx and d$\displaystyle ^2$y/dx$\displaystyle ^2$ at (0,0)
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$\displaystyle \frac {dy} {dx}e^{xy}+ ye^{xy} (y+x \frac {dy} {dx})=cosx $ Solve for dy/dx and try the second derivative.
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