Results 1 to 2 of 2

Math Help - Derivative of inverse function

  1. #1
    Newbie
    Joined
    Sep 2008
    Posts
    1

    Derivative of inverse function

    Hi everybody,

    I got the following:

    f'(x)= xarcsinx - sqrt(1-x^2)
    I use the sum rule and my answer is f(x)=1/sqrt(1-x^2)+1, but I need your approval, because I'm not quite sure. Please give me the whole solution step-by-step so that I can get it. Many thanks in advance!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Banned
    Joined
    Aug 2008
    Posts
    530
    Quote Originally Posted by lookr View Post
    Hi everybody,

    I got the following:

    f'(x)= xarcsinx - sqrt(1-x^2)
    I use the sum rule and my answer is f(x)=1/sqrt(1-x^2)+1, but I need your approval, because I'm not quite sure. Please give me the whole solution step-by-step so that I can get it. Many thanks in advance!
    f'(x) = x. \frac{1}{\sqrt{1-x^2}} + 1.\sin^{-1} x - \frac{-2x}{2 \sqrt{1-x^2}}

    f'(x) = \frac{x}{\sqrt{1-x^2}} + \sin^{-1} x + \frac{x}{\sqrt{1-x^2}}

    f'(x) = \frac{2x}{\sqrt{1-x^2}} + \sin^{-1} x

    Now you solve further.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. derivative of inverse function
    Posted in the Calculus Forum
    Replies: 2
    Last Post: April 17th 2010, 10:42 AM
  2. Derivative of an Inverse function
    Posted in the Calculus Forum
    Replies: 3
    Last Post: January 28th 2010, 08:41 PM
  3. Derivative of inverse function
    Posted in the Calculus Forum
    Replies: 5
    Last Post: November 7th 2009, 09:33 PM
  4. inverse function derivative
    Posted in the Calculus Forum
    Replies: 1
    Last Post: September 3rd 2007, 07:32 PM
  5. inverse function derivative
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 4th 2007, 10:21 AM

Search Tags


/mathhelpforum @mathhelpforum