f(x)=(lnx)^2, x>0

On this particular problem i don't even know how to start so if you would assist me in starting this problem that would be awesome. just help me start and i'm sure i could probably figure out the rest

Printable View

- Sep 24th 2008, 02:46 PMplstevensfind the value of any relative extrema.
f(x)=(lnx)^2, x>0

On this particular problem i don't even know how to start so if you would assist me in starting this problem that would be awesome. just help me start and i'm sure i could probably figure out the rest - Sep 24th 2008, 03:19 PMskeeter
start by finding f'(x) and looking for critical vales ...

for , ... f(x) is decreasing

for , ... f(x) is increasing

so ... what sort of extrema at x = 1?