Hello

This function would be considered a plane. It is continuous everywhere, so it would exist

The same idea applies here as well. It would also existRange

Level curves and contour curves are the same. Let . We see then that the cross section of this plane and the plane will have the form of . Thus, the contour lines will be linear, and as k varies (positive or negative), the contour lines vary.Level curvesIs this also called contour curve?

Here is the contour plot:

Hmm...I would say that the boundary of the domain would be , but if anyone one else wants to chip in something, that would be greatBoundary of the functions domain

Could you try to elaborate a little bit more on this?Determine if open region, closed or neither.

Since the domain approaches both positive and negative infinity, the domain would beDecide if the domain is bounded or unbounded.

Need help with the bolds! Please explain too!unbounded[someone correct me if I'm wrong]