How do you find the radius of convergence for power series like the following: $\displaystyle \sum_{n=1}^\infty (1/n!)*(z-1+i)^{2n}$ $\displaystyle \sum_{n=0}^\infty z^{2n+1}$
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Originally Posted by grad444 $\displaystyle \sum_{n=1}^\infty (1/n!)*(z-1+i)^{2n}$ Hint: Use the fact that $\displaystyle (n!)^{1/n} \to \infty$ and now use the root test. $\displaystyle \sum_{n=0}^\infty z^{2n+1}$ Again use the root test here.
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