
helpp
help with curve sketching, i have a question how do u sketch this,
y= (x2)^3
i know u have to find the roots, but if u get (x2), isn't the root 2, and it goes through a curve because of its to the power of 3?
also one question consider this exmaple. y= 5 (x+5) (x5), would the 5 consider as a root or 0?, and also if a questions like this
y = (x^225)(x^1), would the negative sign be consider the graph as negative parabola? or would the negative sign be ignored?

1. As far as sketching $\displaystyle y = (x  2)^3$, this is simply a right shift of $\displaystyle y = x^3$. You'll need a few points on the graph to help you sketch it. The root is indeed 2. What is y when x = 0?
2. Zero is not a root of $\displaystyle y = 5(x + 5)(x  5)$, because x = 0 gives y = 125. The roots are dependent on the polynomial factors of x + 5 and x  5, not the multiple of 5.
3. In your equation $\displaystyle y = \frac{(x^2  25)}{x}$ the negative sign is not ignored. You can distribute it across to yield the equation $\displaystyle y = \frac{25  x^2}{x}$. Additionally, this graph is not a parabola. When I write it in this form, can you see why?