I'm confused a bit by your wording. Are you saying f(x)=6x^2..... and you need to find the tangent line to f(x) at x=-2?
Can anyone help me out... I know that on problem like you find the derivtive of those using simple differentiation, and them combine and so on.
However, I'm not sure how to do this: find the equation of a tangent line to the graph of f using x=-2 on an equation of
I thought that was the derivative, how can this be accomplished. Simply plugging in -2 did not work. .
Ok, so
Plugging in x=-2 gives you the y-value of this point on the function. So you'll have a point (-2, f(-2)).
Now take the derivative of f(x) and plug in -2 to find the slope of the tangent line at x=-2.
Now you have a point and a slope, thus a line can be formed!
Point-slope formula:
is the point on the graph you found and m is the slope at x=-2.
Make sense?