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Math Help - Finding Derivative problems

  1. #1
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    Sep 2008
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    Finding Derivative problems

    I have

    (y^2/y+3)^4


    The answer I keep getting is

    (4y^8+6y)/(y+3)^5

    But i keep getting told that's wrong so I'm not sure where I messed up.
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  2. #2
    Member javax's Avatar
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     <br /> <br />
\left(\frac{y^2}{y+3}\right)^4 = 4\left(\frac{y^2}{y+3}\right)^3\left(\frac{y^2}{y+  3}\right)' =<br />
     <br /> <br />
4 \left( \frac{y^6}{(y+3)^3}\right) \left( \frac{2y(y+3)-y^2}{(y+3)^2}\right)<br />
     <br />
4 \left( \frac{y^6}{(y+3)^3}\right) \left( \frac{y^2+6y}{(y+3)^2}\right)<br />
     <br />
\frac{4y^7(y+6)}{(y+3)^5}<br />
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