Thread: Limits using Trig Functions

Can someone help me with this: Find the limit if the limit exists:

lim x-tanx
x->0 sinx



lim 1 - sine^2 (1)^2
x->-2- t (t)

Originally Posted by Roxanne

Can someone help me with this: Find the limit if the limit exists:

lim x-tanx
x->0 sinx

Mr F says:

lim 1 - sine^2 (1)^2 Mr F says: This is incomprehensible.
x->-2- t (t)

..

find limit if limit exist:

lim 1/t^2 sin^2 (t/2)
x->0

Hello, Roxanne!

If no one is answering, there is confusion in your statement . . .


I must assume it says: .


In the denominator, multiply by

. . .

Originally Posted by Roxanne

find limit if limit exist:

lim 1/t^2 sin^2 (t/2)
x->0

Do you mean ? If so note that:

.