I already update the post, every one look it clear....refer to my post on no 10 & 11

here my problem

Determine the equation of the normal to the curve y = x^3-6x^2-2x which are perpendicular to the straight line 4-x+2y=0

just check my calculation..what wrong??

i already put the actual ans @ pg 2 of 2 at bottom

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actual answers:

y + x + 12 = 0

or

27y + 27x + 4 = 0