f(x)=1/1-2sinx how do you determine that the answer is 2npie+(pie/6), 2npie+(5pie/6), n=0,-1,1,-2,2....
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There are discontinuities when 1-2sinx=0 because the denominator of a fraction cannot be 0.
So whenever sinx=1/2 there will be discontinuities.
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