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Thread: find the discontinuities

  1. Sep 21st 2008, 06:32 PM #1
    vinson24
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    find the discontinuities

    f(x)=1/1-2sinx how do you determine that the answer is 2npie+(pie/6), 2npie+(5pie/6), n=0,-1,1,-2,2....
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  2. Sep 21st 2008, 06:35 PM #2
    Linnus
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    There are discontinuities when 1-2sinx=0 because the denominator of a fraction cannot be 0.

    So whenever sinx=1/2 there will be discontinuities.
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