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Math Help - equation of plane that contains P and perpendicular to line

  1. #1
    uyk
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    equation of plane that contains P and perpendicular to line

    Hi, can anyone help me with the following question?

    Given P=(3, 4,3) and L1=(4-t,3t, -1+t), find the scalar equation of the plane that contains point P and perpendicular to the line L1.

    I know how to figure out the equation that contains point P and L1, but I am not sure this one. So, please help. Thank you
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by uyk View Post
    Hi, can anyone help me with the following question?

    Given P=(3, 4,3) and L1=(4-t,3t, -1+t), find the scalar equation of the plane that contains point P and perpendicular to the line L1.

    I know how to figure out the equation that contains point P and L1, but I am not sure this one. So, please help. Thank you
    the direction vector for the line is <-1, 3, 1 >. use this as the normal vector for the plane. you have a point the plane passes through and the normal vector, you can find the plane
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  3. #3
    Flow Master
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    Quote Originally Posted by uyk View Post
    Hi, can anyone help me with the following question?

    Given P=(3, 4,3) and L1=(4-t,3t, -1+t), find the scalar equation of the plane that contains point P and perpendicular to the line L1.

    I know how to figure out the equation that contains point P and L1, but I am not sure this one. So, please help. Thank you
    The cartesian equation of a plane can be written ax + by + cz = d where the vector <a, b, c> is perpendicular to the plane.

    A vector perpendicular to your plane is a vector parallel to the line: <-1, 3, 1>.

    Get the value of d by substituting (3, 4, 3) into ax + by + cz = d.
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  4. #4
    uyk
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    I see.. Thanks a lot
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