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Math Help - Initial value problem

  1. #1
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    Initial value problem

    Having no luck with this either

    Find the solution of the initial value problem


    dy/dx=(1/2e^-x/4).(y sqrt y) (y>0) y=1/4 when x =0
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by offahengaway and chips View Post
    Having no luck with this either

    Find the solution of the initial value problem


    dy/dx=(1/2e^-x/4).(y sqrt y) (y>0) y=1/4 when x =0
    do you mean y' = \frac 12e^{-x/4} \cdot y \sqrt{y} ?

    if so, this si separable, divide both sides by y \sqrt{y} = y^{3/2} (we can do this since y \ne 0). then, multiply both sides by dx, we get

    \Rightarrow y^{-3/2}~dy = \frac 12e^{-x/4}~dx

    now integrate both sides and continue
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