I'm not sure what to do when I plug in "a" in a rational function if the numerator comes out as zero, here is the problem:
lim (x+2)/(x^3+8)
x--> -2
the answer in the back is 1/12, could someone help me see how to find this?
Thx!!!
I'm not sure what to do when I plug in "a" in a rational function if the numerator comes out as zero, here is the problem:
lim (x+2)/(x^3+8)
x--> -2
the answer in the back is 1/12, could someone help me see how to find this?
Thx!!!
The thing is you got a fraction here:
$\displaystyle \frac {x+2} {x^3 + 8}$
where if you put x = -2 in, both the top and the bottom are zero.
So what you do is you factorise the bottom, and you'll see that it has a factor of x+2. So divide top and bottom by x+2 and see what you're left with.