Originally Posted by

**yoleven** lim y-(4*y^1/2)+3/y^2-1

x-1

I multiplied the numerator and denomination by the conjugate:

y-(4*y^1/2)+3 *y+(4*y^1/2)-3

y^2-1 *y+(4*y^1/2)-3

In the numerator, I get

y^2-16y-9

denomination gives me

y^2-1(y+(4*y^1/2)-3

I can factor the denominator a bit and i'm left with

y^2-16y-9/(y-1)(y+1)*(y+(4*y^1/2)-3

I can see that i should have got a factor of (y-1) in the numerator so that I could cancel the (y-1 ) in the denominator. I'm not sure what I am doing wrong. What did I do wrong and what am I missing?