Hello, need some help on this integral! Thanks
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Originally Posted by javax Hello, need some help on this integral! Thanks Half-angle identities are key in many trig problems. Namely: Back to our integral: Substituting: Simplifying: Let's part out the second integral: Let and Then: Plugging all this in, we get: So:
Last edited by hatsoff; September 19th 2008 at 06:12 PM.
Three things we'll use: And finally: So, in an unconventional way:
Indeed, It seems I cannot integrate by parts this one It's just getting longer...or I'm missing something!
Originally Posted by o_O Three things we'll use: And finally: So, in an unconventional way: Cool, I remember this from the course now...! I have to float on my notebook a bit more Thanks
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