# Math Help - Help with problem

1. ## Help with problem

We just started a new unit and the instructor hasnt explain how to do this even thoug i can tell its simple

Find f '(a).
f(x) = √(3x + 1 )

2. $f'(x) = \frac {3} {2 \sqrt {3x + 1}}$

3. Note that Matt's answer comes from writing the function as $(3x + 1)^{\frac 12}$ and applying the chain rule

the chain rule says: $\frac d{dx}f(g(x)) = f'(g(x)) \cdot g'(x)$

here, $f(x) = x^{\frac 12}$ and $g(x) = 3x + 1$