how would i integrate this: 18/((x+3)(x^2+9)) tried doing the partial fraction method on it, and i cant find the values of A and B for: A/(x+3) + B/(x^2+9)
how would i integrate this: 18/((x+3)(x^2+9)) tried doing the partial fraction method on it, and i cant find the values of A and B for: A/(x+3) + B/(x^2+9)
Since $\displaystyle x^2 + 9$ is an irreducible quadratic, its contribution to the partial fraction decomposition is $\displaystyle \frac{Bx + C}{x^2 + 9}$, NOT $\displaystyle \frac{B}{x^2 + 9}$.