can someone check my answer

Id check it myself but its a even problem(Rofl)

$\displaystyle

\frac {1}{t^2+3t-1}

$

$\displaystyle

(t^2+3t-1)^{-1}

$

$\displaystyle

-1(t^2+3t-1)^{-2}(2t+3)

$

$\displaystyle

- \frac {2t+3}{(t^2+3t-1)^2}

$

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- Sep 18th 2008, 08:54 PMjohn doederivative problem
can someone check my answer

Id check it myself but its a even problem(Rofl)

$\displaystyle

\frac {1}{t^2+3t-1}

$

$\displaystyle

(t^2+3t-1)^{-1}

$

$\displaystyle

-1(t^2+3t-1)^{-2}(2t+3)

$

$\displaystyle

- \frac {2t+3}{(t^2+3t-1)^2}

$ - Sep 18th 2008, 08:56 PM11rdc11
Looks correct(Clapping)

- Sep 19th 2008, 01:53 AMJames Bond007
Try doing the same problem using the 1st principle(Giggle)