Could someone please help!!

Find the horizontal asymptote of arccot(x^2-x^4)

thanks so much!!

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- Sep 18th 2008, 01:42 PMhenry5finding horizontal asymptotes
Could someone please help!!

Find the horizontal asymptote of arccot(x^2-x^4)

thanks so much!! - Sep 18th 2008, 01:50 PMChris L T521
Horizontal Asymptotes occur when $\displaystyle f'(x)=0\text{ or }f'(0)$ is undefined.

$\displaystyle f'(x)=-\frac{2x-4x^3}{1+(x^2-x^4)^2}$

$\displaystyle f'(x)=0$ when $\displaystyle -2x+4x^3=0$. I leave it for you to find the values of x that cause this to be true.

I gave enough info to help get you through the problem. Try to finish this off.

--Chris - Sep 18th 2008, 02:41 PMhenry5
thanks for the reply

the x values that i get are +/- square root of 0.5 and 0.

the question though asks for the y values (like horizontal asymptote at y=2)

how would i find this?