# finding horizontal asymptotes

Printable View

• Sep 18th 2008, 01:42 PM
henry5
finding horizontal asymptotes
Could someone please help!!

Find the horizontal asymptote of arccot(x^2-x^4)

thanks so much!!
• Sep 18th 2008, 01:50 PM
Chris L T521
Quote:

Originally Posted by henry5
Could someone please help!!

Find the horizontal asymptote of arccot(x^2-x^4)

thanks so much!!

Horizontal Asymptotes occur when $f'(x)=0\text{ or }f'(0)$ is undefined.

$f'(x)=-\frac{2x-4x^3}{1+(x^2-x^4)^2}$

$f'(x)=0$ when $-2x+4x^3=0$. I leave it for you to find the values of x that cause this to be true.

I gave enough info to help get you through the problem. Try to finish this off.

--Chris
• Sep 18th 2008, 02:41 PM
henry5
thanks for the reply

the x values that i get are +/- square root of 0.5 and 0.

the question though asks for the y values (like horizontal asymptote at y=2)

how would i find this?