Thread: Locate the discontinuities

Can someone tell me if my logic behind this question is correct



the answer is



where 'n' is any integer

logic: since arctangent is the inverse of tangent and



multiplying these boundaries by tan would result in a discontinuity

Originally Posted by silencecloak

Can someone tell me if my logic behind this question is correct



the answer is



where 'n' is any integer

logic: since arctangent is the inverse of tangent and



multiplying these boundaries by tan would result in a discontinuity

your answer is (partially) correct. your logic makes no sense to me though. what does arctan(x) have to do with anything?

Originally Posted by silencecloak

Can someone tell me if my logic behind this question is correct



the answer is



where 'n' is any integer

logic: since arctangent is the inverse of tangent and



multiplying these boundaries by tan would result in a discontinuity

here is a hint:

the domain of the logarithm is the set of positive real numbers. if what is being logged is zero or negative, then the log is undefined.

tangent is discontinuous where cos(x) = 0 and it is zero where sin(x) = 0

Originally Posted by Jhevon

here is a hint:

the domain of the logarithm is the set of positive real numbers. if what is being logged is zero or negative, then the log is undefined.

tangent is discontinuous where cos(x) = 0 and it is zero where sin(x) = 0

so where does the for the answer come from

that's why i was tying arctan in :/

EDIT:

oh wait...we are playing with the unit circle now huh?

cos(90) = 0

but how do you know that the tan is discontinuous where cos(x) = 0 and is zero where sin(x) = 0

We know that because of the identity using . We know that:



So, when



Which is undefined and therefore discontinuous, and when



Which is zero for all nonzero results of , so the logarithm is therefore discontinuous because it is not defined at zero.