Little help please, my answer doesn't check out. need to find the derivative
Problem is e to x-1 / 3x2 -4
thats e to the x-1, divided by 3x squared - 4
I got -6xe to the x-1 divided by 3x squared - 4
(how do you write exponents on this forum)
Little help please, my answer doesn't check out. need to find the derivative
Problem is e to x-1 / 3x2 -4
thats e to the x-1, divided by 3x squared - 4
I got -6xe to the x-1 divided by 3x squared - 4
(how do you write exponents on this forum)
$\displaystyle \frac{d}{dx} \left[\frac{x-1}{3x^2-4}\right]$
$\displaystyle \frac{(3x^2-4)(1) - (x-1)(6x)}{(3x^2-4)^2}
$
$\displaystyle \frac{du}{dx} = -\frac{3x^2 - 6x + 4}{(3x^2-4)^2}$
so ...
$\displaystyle \frac{d}{dx} (e^u) = e^u \cdot \frac{du}{dx} = -e^{\frac{x-1}{3x^2-4}} \cdot \frac{3x^2 - 6x + 4}{(3x^2-4)^2}$