# Math Help - Are between two curves (integration)

1. ## Are between two curves (integration)

Sorry, need help again.. The question is:

Caulculate the area bounded by the graphs of f(x) = x^2, g(x) = 1/x^2, x>0 and the line x = 3.

2. $A = \int_1^3 x^2 - \frac{1}{x^2} \, dx$

3. could you tell me how you arrived at the equation?

4. First equate the two equations to see where the functions intersect.

$x^2 = \frac{1}{x^2}$

which is x= 1

That i going to be the lower bound.

Now notice how x^2 is above 1/x^2 in the interval [1,3]

so subtract the lower function from the higher function

put all that together and you get

$\int_1^3 x^2 - \frac{1}{x^2}$