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Math Help - Are between two curves (integration)

  1. #1
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    Are between two curves (integration)

    Sorry, need help again.. The question is:

    Caulculate the area bounded by the graphs of f(x) = x^2, g(x) = 1/x^2, x>0 and the line x = 3.
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  2. #2
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    A = \int_1^3 x^2 - \frac{1}{x^2} \, dx
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  3. #3
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    could you tell me how you arrived at the equation?
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  4. #4
    Super Member 11rdc11's Avatar
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    First equate the two equations to see where the functions intersect.

    x^2 = \frac{1}{x^2}

    which is x= 1

    That i going to be the lower bound.

    Now notice how x^2 is above 1/x^2 in the interval [1,3]

    so subtract the lower function from the higher function

    put all that together and you get

    \int_1^3 x^2 - \frac{1}{x^2}
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