f(x)= 2secx + tanx for all x in the interval 0 and 2pi Am i supposed to take the derivative of f(x), set it equal to 0, and find all points where x satisfies the equation?
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Hi Originally Posted by NotEinstein f(x)= 2secx + tanx for all x in the interval 0 and 2pi Am i supposed to take the derivative of f(x), set it equal to 0, and find all points where x satisfies the equation? Oh yeah
I'm breaking this problem down, and am stuck at did I mess up the process somewhere, or am i just needing to go further?
Originally Posted by 11rdc11 i got that, but i need to plug in to find points where there is a horizontal tangent.. so now I am trying to simplify this derivative.
Factor out a so now you have and and you don't have to worry about sec(x) = 0 since that is not possible and
Last edited by 11rdc11; September 17th 2008 at 04:16 PM. Reason: Correction forgot the other solution
Originally Posted by 11rdc11 Factor out a so now you have and and you don't have to worry about sec(x) = 0 since that is not possible i followed it all the way til the end. how did you figure that x = 7pi/6?
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