Hello everyone,

Could you please tell me if this looks right?

Find the differential of f(x,y)=square root(x^2+y^3) (1,2)

and estimate f(1.04, 1.98)

fx=1/2(x^2+y^3)^-1/2(2x)

fx(1)=.71

fy=1/2(x^2+y^3)^-1/2(3y^s)

fy(2)=1.7

df=fx(a,b)dx+fy(a,b)dy

df=.71dx+1.7dy

f(1.04, 1.98)=square root(1.04^2+1.98^3)=2.

Thank you very much