[SOLVED] Definite Integral, & Partial fractions

Hi, I have the problem: $\displaystyle \int_{-1}^{3} \frac {x^3+3}{x^2+10x+21}dx$ The denominator was actually $\displaystyle (x+7)(x+3)$ but I know that the degree is higher in the numerator so polynomial long division needs to occur. After I do polynomial division I get $\displaystyle x^2+10x+21 \times \frac {x-10}{207+79x}$after this I get stuck. Usually the denominator has a $\displaystyle x^2$ or higher, then I could break it up but this time it doesn't.

Thanks,

Matt