Okay, yea, once I got the division right everything went well, I know what to do now.
So I now have:
$\displaystyle \int_{-1}^{3} \frac {85}{x+7}- \frac {6}{x+3}dx$ Could I split the integral, integrate and do the limits individually?
Thanks!
Okay, so I did that and I get 36.8285 for the answer, I then calculated it out on my calculator and it got came out to $\displaystyle 85ln(5)-91ln(3)-36$ which is .8285 only, so it's just without the 36. I guess I did something wrong with A and B? I also know that .8285 is the correct answer. I just checked.
I don't mean to be Mr. Picky, but:
$\displaystyle \left(x-10 + \frac{79x+213}{x^2+10x+21}\right) \times (x^2+10x+21)$
$\displaystyle = (x-10)(x^2+10x+21) + 79x + 213$
$\displaystyle = x^3 + 10x^2 + 21x - 10x^2 - 100x - 210 + 79x + 213$
$\displaystyle = x^3 + 3$
$\displaystyle \therefore \frac{x^3+3}{x^2+10x+21} = x-10 + \frac{79x+213}{x^2+10x+21}$
No need to change the integral answers though. The OP should be able to solve them on his own by now...right Matt3D?