If f(x)=x+6, compute f(3) and f'(3). Can someone show me how to do this?
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Originally Posted by VX-1 If f(x)=x+6, compute f(3) and f'(3). Can someone show me how to do this? just plug in 3 for x in the function and then plug in 3 for x in the derivative.
Sorry I didn't clarify-- how would I go about figuring out the derivative in the second one? Would f'(3)=1+6=7 ?
Use the power rule $\displaystyle nx^p = pnx^{p-1}$ n being a constant, so your derivative $\displaystyle f'(x)=1$
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