Can someone help me prove that the limit of (1-secx)/x^2 = -1/2. as x approaches 0, i know (1-cosx)/x^2 is 1/2, and thats it. thanks a bunch. I believe you can use identities or squeeze method, whatever you prefer
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Originally Posted by jarny Can someone help me prove that the limit of (1-secx)/x^2 = -1/2. as x approaches 0, i know (1-cosx)/x^2 is 1/2, and thats it. thanks a bunch. I believe you can use identities or squeeze method, whatever you prefer $\displaystyle \sec x = \frac 1{\cos x}$ plug that in and simplify. the result follows quickly (you will end up with something times the negative of the other limit you mentioned) by the way, you need to say what limit you are taking. the limit as x goes to what?
Originally Posted by jarny Can someone help me prove that the limit of (1-secx)/x^2 = -1/2. as x approaches 0, i know (1-cosx)/x^2 is 1/2, and thats it. thanks a bunch. I believe you can use identities or squeeze method, whatever you prefer
Originally Posted by o_O My apologies to Jarny and my thanks to o_O note to self, read the entire question! words can be boring yes, but if you don't, you'll end up looking like an idiot
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