1. ## Simple indefinate integral

calc test soon, drawing a lot of blanks pon the subject. I have to find the $\displaystyle integral(5x/sqrt(9-4x^2))$. I came up with an answer, but i'm pretty sure i used some steps that you shouldnt ever use in math....so im stuck. Any help? Thanks....

2. $\displaystyle \int \frac{5x}{\sqrt{9-4x^2}} \ dx$

Do a u-sub: $\displaystyle u = 9 -4x^2 \ \Rightarrow \ du = -8x \ dx \iff x dx = -\frac{du}{8}$

Making the subs:
$\displaystyle = \int \frac{5 \ \frac{du}{8}}{\sqrt{u}} = \frac{5}{8} \int \frac{1}{u^{\frac{1}{2}}} \ du$

3. Originally Posted by 92stealth
calc test soon, drawing a lot of blanks pon the subject. I have to find the $\displaystyle integral(5x/sqrt(9-4x^2))$. I came up with an answer, but i'm pretty sure i used some steps that you shouldnt ever use in math....so im stuck. Any help? Thanks....
integration by substitution.

let $\displaystyle u = 9 - 4x^2$

or even better (if you can handle it), let $\displaystyle u^2 = 9 - 4x^2$

4. got it, thank you