Polar Coordinate Integration

Hello,

Having problems setting integration limits due to symmetry.

I have two questions:

One asks to find the volume of the solid formed by the interior of the circle

r = cos(theta) capped by the plane z = x.

Because x = rcos(theta) and r = cos(theta), we have z = (cos(theta))^2

= (1+ cos2(theta))/2, which is the function we integrate.

The volume we wish to find is the right hand side of the lemniscate which is enclosed inside the circle.

For limits for the dr expression we can integrate from b = 1 to a = 0.

For the d(theta) limits I get confused. I was told to integrate the smallest interval possible and multiply by any symmetry factors. With that said, I can take beta = pi/2 and alpha = 0 and multiply by two due to symmetry about the x-axis. However, I know this is not the smallest interval as there must be a ray that caps the lemniscate function. I know how to find this ray, essentially a value for theta, by setting functios r equal to each other and finding that theta. However, I have an expression in terms of r and in terms of z.

My confusion in this next question is much the same as the above:

The question asks to find the volume of the solid based on the interior of the cardioid r = 1 + cos(theta), capped by the cone z = 2 - r.

We have z = 2 - (1 + cos(theta)) = 1 - cos(theta). Essentially another cardioid with the same size but with the cusp pointing in the opposite direction. The graph I get is basically an infinity sign along the y-axis, that is with rays pi/2 and 3pi/2, and with vertices (1,0) and (-1,0).

Again I get confused by symmetry due to the negative and positive contributions of the polar graph. For the d(theta) limits I believe I can integrate from alpha = 0 to beta = pi/2 and multiply by four due to symmetry. I get confused for the dr limits as the solid formed by the two cardioids expands over all four quadrants. Do I integrate from a = o to b = 2 and multiply by two due to symmetry? Two is the intersection point of the

1 + cos (theta) cardiod on the x-axis. I really get confused with this question as I imagine you can integrate from 0 to pi/2, pi/2 to pi, pi to 3pi/2 and 3pi/2 to 2pi breaking up the four quadrants and adding up the volumes of the four regions of the solid.

I would love any hints and any generalizations about symmetry considerations with polar coordinates.

Thank you.

Polar coordinate Integration

Perfect Hacker,

Thank you for your explanations the question with the cardioids is now clear.

However, I do not understand your reply to my first question. I don't see what the surface area has to do with the solid region inside the circle

r = cos(theta) and the plane z = x.

The polar coordinate integration requires dA = rdrd(theta), which is not used in your explanation.

The graph I obtain has the right hand of the lemniscate inside of the circle.

I used z = x = rcos(theta)

Therefore, z = cos(theta)cos(theta) = (1 + cos2(theta))/2. This is the function we integrate right.

So the limits can be from r = cos(theta) to r = 0 right?!

I am not sure about the other limits though, would it be from pi/2 to 0 and multiply by two because of symmetry?

Thanks again.

Polar Coordinate Integration

Perfect Hacker,

I finished doing the question with the two cardioids. Unless I have made some mistakes, working out the integrals for 2r - r^2 was very labourious. I got an answer of -28/9 for the volume of the solid formed by the two cardioiods. Does a negative volume make any sense?

Thank you again.

Polar coordinate integration

Perfect Hacker,

Thank you again for the question with the cardiods. The limits you proposed the first time were incorrect. With the new limits you suggested, I got the same volume as you did by either adding up the left and the right side, or by computing either and multiplying by two due to symmetry.

Like I said before, quite a labourious question with all the trigonometric substitutions.

I am confident that I did the other question correctly, the one you misunderstood as surface area instead of volume.

For d(theta) limits I integrated from 0 to pi/2 and multiplied by two due to symmetry, and for dr limits, I integrated from 0 to cos(theta). The function I integrated was (1+ cos2(theta))/2. Please correct me if I am wrong.

Thanks again.