How do you evaluate this integral?

**mojo0716** · September 15th 2008, 03:48 AM

$\int{1^2x*5^(2x^(2))}$

thanks

**Chop Suey** · September 15th 2008, 04:00 AM

Did you mean:
$\int (1^{2x})(5^{2x^{2}}) dx$

**mr fantastic** · September 15th 2008, 04:00 AM

Originally Posted by mojo0716

$\int{1^2x*5^(2x^(2))}$

thanks

Have you viewed what you've posted .....?

The current formatting of your question makes it unintelligible.

**mojo0716** · September 15th 2008, 04:07 AM

Originally Posted by Chop Suey

Did you mean:
$\int (1^{2x})(5^{2x^{2}}) dx$

Sorry, couldn't figure out how to format it.

it's actually

int ((1^2*(x))*5^(2x^(2)))

$\int (1^{2}x)(5^{2x^{2}}) dx$

**mr fantastic** · September 15th 2008, 04:12 AM

Originally Posted by mojo0716

Sorry, couldn't figure out how to format it.

it's actually

int ((1^2*(x))*5^(2x^(2)))

$\int (1^{2}x)(5^{2x^{2}}) dx$ [/

I'm still as much in the dark as ever. Nevertheless, taking it on face value as $\int (1^{2}x)(5^{2x^{2}}) dx$ you should first realise that this is the same as $\int (x) (5^{2x^{2}}) dx$ . Now make the substitution $u = 2x^2$ and note that $5^u = e^{(\ln 5) u}$ .

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