# Thread: How do you evaluate this integral?

1. ## How do you evaluate this integral?

$\displaystyle \int{1^2x*5^(2x^(2))}$

thanks

2. Did you mean:
$\displaystyle \int (1^{2x})(5^{2x^{2}}) dx$

3. Originally Posted by mojo0716
$\displaystyle \int{1^2x*5^(2x^(2))}$

thanks
Have you viewed what you've posted .....?

The current formatting of your question makes it unintelligible.

4. Originally Posted by Chop Suey
Did you mean:
$\displaystyle \int (1^{2x})(5^{2x^{2}}) dx$
Sorry, couldn't figure out how to format it.

it's actually

int ((1^2*(x))*5^(2x^(2)))

$\displaystyle \int (1^{2}x)(5^{2x^{2}}) dx$

5. Originally Posted by mojo0716
Sorry, couldn't figure out how to format it.

it's actually

int ((1^2*(x))*5^(2x^(2)))

$\displaystyle \int (1^{2}x)(5^{2x^{2}}) dx$[/
I'm still as much in the dark as ever. Nevertheless, taking it on face value as $\displaystyle \int (1^{2}x)(5^{2x^{2}}) dx$ you should first realise that this is the same as $\displaystyle \int (x) (5^{2x^{2}}) dx$. Now make the substitution $\displaystyle u = 2x^2$ and note that $\displaystyle 5^u = e^{(\ln 5) u}$.