How do you evaluate this integral?

• Sep 15th 2008, 03:48 AM
mojo0716
How do you evaluate this integral?
$\displaystyle \int{1^2x*5^(2x^(2))}$

thanks
• Sep 15th 2008, 04:00 AM
Chop Suey
Did you mean:
$\displaystyle \int (1^{2x})(5^{2x^{2}}) dx$
• Sep 15th 2008, 04:00 AM
mr fantastic
Quote:

Originally Posted by mojo0716
$\displaystyle \int{1^2x*5^(2x^(2))}$

thanks

Have you viewed what you've posted .....?

The current formatting of your question makes it unintelligible.
• Sep 15th 2008, 04:07 AM
mojo0716
Quote:

Originally Posted by Chop Suey
Did you mean:
$\displaystyle \int (1^{2x})(5^{2x^{2}}) dx$

Sorry, couldn't figure out how to format it.

it's actually

int ((1^2*(x))*5^(2x^(2)))

$\displaystyle \int (1^{2}x)(5^{2x^{2}}) dx$
• Sep 15th 2008, 04:12 AM
mr fantastic
Quote:

Originally Posted by mojo0716
Sorry, couldn't figure out how to format it.

it's actually

int ((1^2*(x))*5^(2x^(2)))

$\displaystyle \int (1^{2}x)(5^{2x^{2}}) dx$[/

I'm still as much in the dark as ever. Nevertheless, taking it on face value as $\displaystyle \int (1^{2}x)(5^{2x^{2}}) dx$ you should first realise that this is the same as $\displaystyle \int (x) (5^{2x^{2}}) dx$. Now make the substitution $\displaystyle u = 2x^2$ and note that $\displaystyle 5^u = e^{(\ln 5) u}$.