$\displaystyle \int{1^2x*5^(2x^(2))}$

thanks

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- Sep 15th 2008, 03:48 AMmojo0716How do you evaluate this integral?
$\displaystyle \int{1^2x*5^(2x^(2))}$

thanks - Sep 15th 2008, 04:00 AMChop Suey
Did you mean:

$\displaystyle \int (1^{2x})(5^{2x^{2}}) dx$ - Sep 15th 2008, 04:00 AMmr fantastic
- Sep 15th 2008, 04:07 AMmojo0716
- Sep 15th 2008, 04:12 AMmr fantastic
I'm still as much in the dark as ever. Nevertheless, taking it on face value as $\displaystyle \int (1^{2}x)(5^{2x^{2}}) dx$ you should first realise that this is the same as $\displaystyle \int (x) (5^{2x^{2}}) dx$. Now make the substitution $\displaystyle u = 2x^2$ and note that $\displaystyle 5^u = e^{(\ln 5) u}$.