# functionnal equation

• Aug 14th 2006, 11:22 AM
tize
functionnal equation
Hello !
I have a problem to solve this question :
Find all real continuous functions f verifing : f(x+1)=f(x)+f(1/x)
Have you ever seen this, could you help me please ?
• Aug 14th 2006, 12:49 PM
ThePerfectHacker
There is something that bothers me. You say that [tex]f[tex] is countinous on the number line. Yet, it is undefined for any negative integer!
• Aug 19th 2006, 04:16 AM
CaptainBlack
Quote:

Originally Posted by tize
Hello !
I have a problem to solve this question :
Find all real continuous functions f verifing : f(x+1)=f(x)+f(1/x)
Have you ever seen this, could you help me please ?

Can you tell us some of background to this equation,
its context etc?

RonL
• Aug 19th 2006, 12:12 PM
tize
I would like but I don't know anything about this function except that it is continuous. Somebody ask me about such a function and I don't know where does it come from ...
• Aug 19th 2006, 05:46 PM
ThePerfectHacker
Quote:

Originally Posted by tize
I would like but I don't know anything about this function except that it is continuous. Somebody ask me about such a function and I don't know where does it come from ...

What makes it unusual that is a composition of,
$f(1/x)$ which usually are not solved for in functional equations.
• Aug 19th 2006, 09:25 PM
Jameson
Like PH said, this has a cyclical property to it and try replacing all x's with 1/x. The right side of the equation yields the same thing, showing that $f(\frac{1}{x}+1)=f(x+1)$.
• Aug 21st 2006, 12:57 AM
tize
Yes we can already proove that :
$f(0)=f(\Phi^{-1})=f(-\Phi)=0$ where $\Phi$ is the Gold number : $\frac{1+\sqrt 5}{2}$
and
$f$ has a limit when $x\rightarrow\infty$, $f\rightarrow f(1)$