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Thread: Integral

  1. #1
    Member javax's Avatar
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    Integral

    Hello!
    $\displaystyle
    \int{\frac{dx}{x\sqrt{x^2-2x-1}}}
    $

    Using the Euler substitutions $\displaystyle \sqrt{x^2-2x-1} = t-x$, I come up with the result $\displaystyle 2\arctan{(\sqrt{x^2-2x-1}+x)}. $Is the result right? I'm kinda suspicious!

    Thanks
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  2. #2
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    Your answer is correct.
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