1. ## Finding area

how would i find the area of everything under that curve???

the drawing is actually wrong but, its supposed to be part of the curve is over a 6 by 6 square (if you connect the dots), umm..just pretend where the curve ends, it is at (6,0) and it is all contained inside from (0,0) to (6,0)

2. Hmm you would use a Riemann sum or integral but I vaguely remember there is another way.

3. Originally Posted by realintegerz

how would i find the area of everything under that curve???

the drawing is actually wrong but, its supposed to be part of the curve is over a 6 by 6 square (if you connect the dots), umm..just pretend where the curve ends, it is at (6,0) and it is all contained inside from (0,0) to (6,0)
divide the area up into a grid of 1x1 squares, and just count them off to get the area

we can't use anything as sophisticated as Riemann sums or integrals since we don't know what function we are dealing with

4. Originally Posted by Jhevon
divide the area up into a grid of 1x1 squares, and just count them off to get the area

we can't use anything as sophisticated as Riemann sums or integrals since we don't know what function we are dealing with
True sorry thats what I meant since there is no function. Wouldn't an approximation for the area be a 6X6 square so the area should be around 36. Since the area above y=6 would kind of fill the area below the y=6?

5. Originally Posted by 11rdc11
True sorry thats what I meant since there is no function. Wouldn't an approximation for the area be a 6X6 square so the area should be around 36. Since the area above y=6 would kind of fill the area below the y=6?
that sounds like a good approximation. it should be a little more than 36 though, since the area above seems a bit larger than the area below. but 36 is a good first guess i think

6. yeah i was thinking i could just do 36...thanks