Apply difference of squares to the numerator.
Recall that . Bring down the power and something should cancel
lim x->ln2 of (e^2x - 4) / (e^x - 2)
when ln2 is plugged in, there is an answer of 0/0 which is not what im looking for so i need to somehow factor it or something
lim x->6 of [ln(x-5)] / [ln(x-5)^3]
when 6 is plugged in, there is an answer of 0/0 which is again not what im looking for so i need to somehow factor it
PLEASE HELP! THANKS