i cannot figure this out for the life of me.. find the volume of these functions using disk method:
y^2= x , x = 2y ; flip about the y - axis...
answer is 64pie/15
i m sure not getting that..
So the area in question is the area bounded by the two curves $\displaystyle x = y^2; x = 2y$ and rotated around the y-axis. You can solve this by using washers or cylinders. If you use washers, the integral will be $\displaystyle \int _0 ^2 \pi(4y^2 - y^4) dy$.