i cannot figure this out for the life of me.. find the volume of these functions using disk method: y^2= x , x = 2y ; flip about the y - axis... answer is 64pie/15 i m sure not getting that..
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Originally Posted by Legendsn3verdie i cannot figure this out for the life of me.. find the follow of these functions using disk method: y^2= x , x = 2y ; flip about the y - axis... answer is 64pie/15 i m sure not getting that.. look up the disk method, and make sure you understand how i set up the integral below the volume is given by
So the area in question is the area bounded by the two curves and rotated around the y-axis. You can solve this by using washers or cylinders. If you use washers, the integral will be .
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Just for fun, let's do it with shells and see if we get the same thing. Also, from now on, anyone caught spelling 'pi' as 'pie' will be sent to a work camp.
Originally Posted by galactus Also, from now on, anyone caught spelling 'pi' as 'pie' will be sent to a work camp. haha, i caught that too. but i couldn't be bothered to point it out...yet again
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