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Math Help - Calculus 4: P=f(t,c)

  1. #1
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    Calculus 4: P=f(t,c)

    Hello everyone,

    Could someone please tell me if this is correct?

    P=f(t,c)

    Evaluate ft and fc.

    My attempt:

    ft(t,c)-->ft(18,6)=

    fc=(c,t)-->fc(18,6)=

    Thank you very much
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  2. #2
    Super Member Aryth's Avatar
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    What do you mean by ft and fc, do you mean:

    f_t and f_c as in, partial derivatives, or do you mean:

    ft and fc for something else?
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  3. #3
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    Sorry, I mean and as in, partial derivatives.

    Could you please tell me if what I said was correct?

    Thank you
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  4. #4
    Super Member Aryth's Avatar
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    More questions:

    What is the function P, is there any equation or anything?

    And why does f_t(t,c) \rightarrow f_t(18,6)

    There's really no way to verify what you have... There's nothing to compare your answer to...
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