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Math Help - Calculus

  1. #1
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    Calculus

    If anyone could please answer any of these questions i will highly appreciate it

    find dy(over)dx or f'(x) for the following:

    1) f(x) = 4x^3 + 6x^2 - 7x - 5

    2) y = 15x^2 - 8x - 7

    3) y = x^4 - 6x^3 - 6x^2 - 8x

    4) f(x) = 9 - 36x - 3x^2 + 2x^3
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  2. #2
    MHF Contributor
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    All of these can be answered using the power rule and the addition rule: \frac{d}{dx} x^n = nx^{n-1} and h(x) = f(x) + g(x) implies h'(x) = f'(x) + g'(x)
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  3. #3
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    Quote Originally Posted by Brownhash View Post
    If anyone could please answer any of these questions i will highly appreciate it

    find dy(over)dx or f'(x) for the following:

    1) f(x) = 4x^3 + 6x^2 - 7x - 5

    2) y = 15x^2 - 8x - 7

    3) y = x^4 - 6x^3 - 6x^2 - 8x

    4) f(x) = 9 - 36x - 3x^2 + 2x^3
     \left( 1 \right){\text{  }}y = 4x^3  + 6x^2  - 7x - 5 \hfill \\

     \frac{{dy}}<br />
{{dx}} = 12x^2  + 12x - 7 \hfill \\

     \left( 2 \right){\text{  }}y = 15x^2  - 8x - 7 \hfill \\

      \frac{{dy}}<br />
{{dx}} = 30x - 8 \hfill \\

     \left( 3 \right){\text{  }}y = x^4  - 6x^3  - 6x^2  - 8x \hfill \\

    \frac{{dy}}<br />
{{dx}} = 4x^3  - 18x^2  - 12x - 8 \hfill \\

     \left( 4 \right){\text{  }}y = 9 - 36x - 3x^2  + 2x^3  \hfill \\

     \frac{{dy}}<br />
{{dx}} =  - 36 - 6x + 6x^2  \hfill \\
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