Can I get some help in finding the limit of the following trigonometric function?
Lt sin(a+3h)-3sin(a+h)+3sin(a+h)-sin a
h-->0 h^3
the h in the denominator is cube.
the denominator is sin(a+3h)-3sin(a+2h)+3sin(a+h)-sin a
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Can I get some help in finding the limit of the following trigonometric function?
Lt sin(a+3h)-3sin(a+h)+3sin(a+h)-sin a
h-->0 h^3
the h in the denominator is cube.
the denominator is sin(a+3h)-3sin(a+2h)+3sin(a+h)-sin a
Is your question like this:Quote:
Originally Posted by tariq_h_tauheed
or is your question like this:
Hello, tariq_h_tauheed!
Where did this problem come from?
It looks like we walked in on the middle of someone's work . . .
Quote:
 - \overbrace{3\sin(a+h) + 3\sin(a+h)}^{\text{Don't these cancel?}} - \sin(h)}{h^3} )
Could it be: .
If so, we have a chance of solving it . . . otherwise, forget it!