I have a concept question hopefully you guys can help me with. I was asked on a recent exam to find 3 other solutions for vector A that will make the statement true.
j x A = 2i + 3k
Since Vector <2, 0 , 3> is shown in the picture below, I used the right hand rule and curled towards x axis so that my thumb points inwards. From what I learned, this should mean that
Vector A can be
i,<2,0,0>,<3,0,0> for the statement to be true right?