for y=1/(sqrt(x)) find slope of tangent line at the point where x=a then, find the equation of the tangent line at (4,1/2)
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Take the first derivative and replace x with a to find your slope at point a. For the second problem do this when you find out what the slope is plug it into m being the slope
Originally Posted by mono1357 for y=1/(sqrt(x)) find slope of tangent line at the point where x=a then, find the equation of the tangent line at (4,1/2) The slope of the tangent line at is just Thus, . Thus, at , Now, let's find the equation of the tangent line: Since , we now see that Does this make sense? --Chris
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