Originally Posted by

**cyber_ninja83** I am having trouble with Riemann sum for a geometric series. The question prompted me to find the area of the region beneath the curve of e^x from x = 0 to x = 1.

Here is what I have so far:

change in x = 1/n

xi = i/n

f(x) = e^x

f(xi ) = e^(i/n)

Area = lim as n goes to infinity of the sum from i = 1 to n of e^(i/n) times 1/n

then, since this is a geometric sequence, it can be simplified to:

Area = lim as n goes to infinity of 1/n * e^(1/n) * (e-1)/(e^(1/n)-1)

i have no clue how to solve this limit. I tried l'Hopital's rule, but got nowhere. Any help is very much appreciated.